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September 30, 2014

September 30, 2014

Posted by **Herosugar** on Wednesday, October 10, 2012 at 11:39pm.

Find the moment of inertia about each of the following axes for a rod that is 0.300 in diameter and 1.60 long, with a mass of 5.00×10−2 .

How do you find this ? I know how to find the perpendicular and end .

but this?

About an axis along the length of the rod.

- College Physics -
**Elena**, Thursday, October 11, 2012 at 6:57pmIf the rod has a measurable radius, it is a cylinder.

The moment of inertia of cylinder about the axis passing through its center

is

I=mR²/2=mD²/8 = 5•10⁻⁴•0.3²/8 =…

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