calculus
posted by Anonymous .
a man on a dock is pulling in a boat by means of a rope attached to the bow of the boat 1ft above the water level and passing through a simple pulley located on a dock 8ft above the water level. if he pulls in the rope at a rate of 2ft/sec, how fast is the boat approaching the dock when the bow of the boat is 24ft from the point that is directly below the pulley?

consider y=0 at the bot bow, so the pulley is at height 7
if the boat is at distance x, the length r of the rope from pulley to boat, is given by
r^2 = x^2 + 7^2
when x=24, r=25
dr/dt = 2
2r dr/dt = 2x dx/dt
2(25)(2) = 2(24) dx/dt
dx/dt = 25/12 ft/s 
how ambiguous a way to present the problem