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March 27, 2015

March 27, 2015

Posted by **Taylor** on Wednesday, October 10, 2012 at 9:40pm.

I've tried tan 20= gr/v^2 = (9.8)(.8)/v^2 = 4.7 m/s and that's not the correct answer (online homework). Any help or explanation would be appreciated

- College Physics -
**Elena**, Thursday, October 11, 2012 at 7:16pmmg=Tsin α

mv²/R=Tcos α

mgR/ mv² = Tsin α/Tcos α

gR/ v² =tan α

gLcos α/ v² =tan α

v=sqrt{ gLcos α/ tan α} =sqrt{9.8•0.8•cos20°/tan20°} = 4.5 m/s

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