Homework Help: Physics

Posted by Anonymous on Wednesday, October 10, 2012 at 2:11pm.

In tests on earth a lunar surface exploration vehicle (mass = 5.90 103 kg) achieves a forward acceleration of 0.215 m/s2. To achieve this same acceleration on the moon, the vehicle's engines must produce a drive force of 1.64 103 N. What is the magnitude of the frictional force that acts on the vehicle on the moon?

Physics - Henry, Thursday, October 11, 2012 at 7:34pm
Fap - Ff =ma.
1640 - Ff = 5900*0.215 = 1269 N.
-Ff = 1269 - 1640 = -371
Ff = 371 N. = Force of friction.

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