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October 20, 2014

October 20, 2014

Posted by **Purnima** on Wednesday, October 10, 2012 at 12:41pm.

- physics -
**Damon**, Wednesday, October 10, 2012 at 1:16pmif of a solid disc around an axis through the center and perpendicular to the surface (an axle)

radius R, thickness t

mass M = rho (volume) = rho(pi R^2 t)

I = rho *t* integral 2 pi r^3 dr

= t rho (2 pi)R^4/4 = t rho pi R^4/2

but rho t = M/pi R^2

so

I = M R^2/2

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