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December 20, 2014

December 20, 2014

Posted by **TUHITUHI** on Wednesday, October 10, 2012 at 10:35am.

- math -
**Steve**, Wednesday, October 10, 2012 at 11:11am(a-b)^2 + (a-c)^2 + (b-c)^2 >= 0

a^2 - 2ab + b^2 + a^2 - 2ac + c^2 + b^2 - 2bc + c^2 >= 0

2a^2 + 2b^2 + 2c^2 - 2(ab+ac+bc) >= 0

divide by 2.

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