Find the number of cells present after 9 days given the function:
f(x)=111.6e^(.44794t)+288.4
what's the problem? Just plug in t=9 (assuming f(t) is the number of cells after t days).
6576
To find the number of cells present after 9 days, we need to substitute the value of 9 into the function f(x).
The given function is: f(x) = 111.6e^(0.44794t) + 288.4
First, we substitute the value t = 9 into the function:
f(9) = 111.6e^(0.44794 * 9) + 288.4
To find the value of e^(0.44794 * 9), we can use a calculator or a math software. Let's calculate it using a calculator:
e^(0.44794 * 9) = 459.3583461
Now we substitute this value back into the function:
f(9) =111.6 * 459.3583461 + 288.4
Calculating this expression gives us:
f(9) = 50986.307368 + 288.4
f(9) = 51274.707368
Therefore, the number of cells present after 9 days is approximately 51274.707368.