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September 18, 2014

September 18, 2014

Posted by **liam** on Wednesday, October 10, 2012 at 7:32am.

What is the wind velocity?

- science -
**bobpursley**, Wednesday, October 10, 2012 at 8:09amdraw the figure. For wind speed, use the law of cosines:

speed^2=200^2+220^2-2*200*220Cos20

make certain from your diagram you understand that.

Now, the hard part, the direction. Label the diagram, ABC, where A is at the origin, and you go CLOCKWISE around the triangle. You need angle B or C, then convert that to axis angles.

Lets do angle B.

Law of sines:

220/sinB=windspeedabove/sin20

solve for angle B. Now, that is the angle in the triangle. The direction then is, since it is measured against an axis, the direction is 90-B South of East. Check that carefully.

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