Saturday

January 31, 2015

January 31, 2015

Posted by **Alex** on Wednesday, October 10, 2012 at 1:24am.

(2cosx+3cosx-2)/(2cosx-1)as x tends to pi/3.

- Math -
**Steve**, Wednesday, October 10, 2012 at 10:30amif you let y=cosx, then you have

(2u-1)(u+2)/(2u-1)

so, except when u=1/2, you just have (u+2)

so, the limit is cos pi/3 + 2 = 5/2

there is a removable hole at x=pi/3

**Answer this Question**

**Related Questions**

Math - Solving for Trig Equations - For the following equation, why cannot I not...

Calculus - Determine the concavity and find the points of inflection. y=2cosx + ...

Pre Calculus - Having trouble verifying this identity... cscxtanx + secx= 2cosx ...

Trig - prove the identity (sinX)^6 +(cosX)^6= 1 - 3(sinX)^2 (cosX)^2 sinX^6= ...

trig - prove that (2cosx+1)(2cosx-1)= 1 +2cos2x

math - tanx+secx=2cosx (sinx/cosx)+ (1/cosx)=2cosx (sinx+1)/cosx =2cosx ...

derivatives - x^2cosx-2xsinx-2cosx

RSNHS - What is the limit of 1-2x^2 -2cosx + cos^2x all over x^2? please answer ...

RESPONSE to PreCalc Question - h t t p : / / w w w . j i s k h a . c o m / d i s...

pre-cal - find all solutions in interval [0,2pi] tan²x = -3/2 secx This question...