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Math

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Find the limit of
(2cosx+3cosx-2)/(2cosx-1)as x tends to pi/3.

  • Math - ,

    if you let y=cosx, then you have

    (2u-1)(u+2)/(2u-1)

    so, except when u=1/2, you just have (u+2)

    so, the limit is cos pi/3 + 2 = 5/2

    there is a removable hole at x=pi/3

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