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Posted by **ladybug** on Tuesday, October 9, 2012 at 9:39pm.

In(x/x-5)+In(x+5/x)-In(x^2-25)

- pre-calculus -
**Reiny**, Tuesday, October 9, 2012 at 10:24pmAssuming you meant:

In(x/(x-5))+In((x+5)/x)-In(x^2-25)

= lnx - ln(x-5) + ln(x+5) - lnx - ( ln(x+5) + ln(x-5) )

= lnx - ln(x-5) + ln(x+5) - lnx - ln(x+5) - ln(x-5)

= -2ln(x-5)

or -ln(x-5)^2 or ln(x-5)^-2

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