A 1720-kg car is traveling with a speed of 15.0 m/s. What is the magnitude of the horizontal net force that is required to bring the car to a halt in a distance of 47.0 m?

idk

To find the magnitude of the horizontal net force required to bring the car to a halt, we can use the equations of motion.

The first equation we can use is the equation of motion for deceleration:

v^2 = u^2 + 2as

where:
v = final velocity (0 m/s, since the car comes to a halt)
u = initial velocity (15.0 m/s)
a = acceleration
s = displacement (47.0 m)

Rearranging the equation to solve for acceleration (a):

a = (v^2 - u^2) / (2s)

Substituting the known values:

a = (0^2 - 15.0^2) / (2 * 47.0)

Simplifying the equation further:

a = (-225) / 94

Now we have the acceleration, which is the rate at which the car slows down. To find the net force, we can use Newton's second law of motion:

F = ma

where:
F = net force
m = mass of the car (1720 kg)
a = acceleration (-225 / 94)

Substituting the known values:

F = 1720 * (-225 / 94)

Calculating the magnitude of the horizontal net force:

|F| = |1720 * (-225 / 94)|

|F| = 4096.81 N (rounded to two decimal places)

Therefore, the magnitude of the horizontal net force required to bring the car to a halt in a distance of 47.0 m is approximately 4096.81 N.