Homework Help: Chemistry

Posted by Syed on Tuesday, October 9, 2012 at 8:32pm.

A gas is allowed to expand at constant temperature from a volume of 2.00 L to 11.20 L against an external pressure of 1.500 atm. If the gas loses 256 J of heat to the surroundings, what are the values of q, w, and ΔU? Pay careful attention to units.

-----My attempt:

q = heat
so if the gas losses 256J of heat then that makes

q=-256J

as for w

w = -p (delta V)
w = -( 1.5atm) (11.20L-2.0L)
w = -13.8atm (convert this to J)
w = -13.8atm * (8.3145 J K^-1 mol^-1)/(0.08206 L atm K^-1 mol^-1)

w= - 1398.2J?

then Delta U = q + w
delta U = -256J + (-1398.2J)
delta U = 1654J?

Is this right?

No one has answered this question yet.

Answer this Question

Related Questions

Chemistry - Consider an ideal gas encloesd in a 1.00 L container at an internal ...
Chemistry - Consider an ideal gas encloesd in a 1.00 L container at an internal ...
chemistry - A sample of an ideal gas at 15.0 atm and 10.0 L is allowed to expand...
q, w, and DU - A gas is allowed to expand at constant temperature from a volume ...
Chemistry - A gas is allowed to expand at constant temperature from a volume of ...
chemistry - A sample of an ideal gas at 15.0 atm and 10.0 L is allowed to expand...
Chemistry - A sample of an ideal gas at 15.0 atm and 10.0 L is allowed to expand...
chemistry - An ideal gas is allowed to expand isothermally from 2.00 L at 5.00 ...
thermodynamics and kinetics - One mole of an ideal gas at 25C and 1 bar is ...
chemistry - An ideal gas is allowed to expand from 7.40 L to 55.5 L at constant ...

For Further Reading

First Name:
School Subject:
Answer: