A truck carrying a 65.4 kg crate accelerates from rest to 53.9 km/h on a flat horizontal surface in 15.2 seconds. The crate does not slip in the truck bed. The acceleration was not constant. How much work was done on the crate by the truck?

K = 1/2 * m * v^2

Convert km/h to m/s, and solve for K

To find the work done on the crate by the truck, we need to use the work-energy principle. The work done is equal to the change in kinetic energy of the crate.

The formula for work done is:

Work = Change in Kinetic Energy

The change in kinetic energy is equal to the final kinetic energy minus the initial kinetic energy. The initial kinetic energy is zero since the crate starts from rest.

The formula for kinetic energy is:

Kinetic Energy = 0.5 * mass * velocity^2

Using this formula, we can calculate the final kinetic energy of the crate.

First, we need to convert the given final velocity from km/h to m/s. We know that 1 km/h is equal to 0.2778 m/s.

Final velocity = 53.9 km/h * (0.2778 m/s / 1 km/h) = 14.97 m/s

Now we can calculate the final kinetic energy:

Final kinetic energy = 0.5 * 65.4 kg * (14.97 m/s)^2

Now we need to calculate the initial kinetic energy, which is zero.

Initial kinetic energy = 0.5 * 65.4 kg * (0 m/s)^2 = 0

Finally, we can subtract the initial kinetic energy from the final kinetic energy to find the change in kinetic energy, which gives us the work done on the crate by the truck.

Work = Final kinetic energy - Initial kinetic energy

Work = (0.5 * 65.4 kg * (14.97 m/s)^2) - 0

After performing the calculation, the work done on the crate by the truck is the final result.