What is the inverse of y = (3/7)x + 9
I know you have to switch x and y so I get to x-9=(3/7)y
from there I don't know what to do.
You now solve this new equation for y
x = (3/7)y + 9 , (you did not switch the x and y )
times 7
7x = 3y + 63
7x - 63 = 3y
y = (7/3)x - 21
then solve for y:
x = (3/7)y + 9
x-9 = (3/7) y
7/3 (x-9) = y
ta-da!
steve can u help me
To find the inverse of a function, you need to solve for y in terms of x. Starting from the equation you have: x - 9 = (3/7)y
To isolate y, you can follow these steps:
1. Multiply both sides of the equation by (7/3) to eliminate the fraction:
(7/3)(x - 9) = (3/7)y * (7/3)
Simplifying:
(7/3)x - 21 = y
2. Now, rewrite the equation to show y as the subject:
y = (7/3)x - 21
So, the inverse of the function y = (3/7)x + 9 is y = (7/3)x - 21.
To summarize the process:
1. Start by switching x and y in the original equation.
2. Rearrange the equation to isolate y.
3. Simplify the equation to express y in terms of x.
That's how you find the inverse of a function.