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September 18, 2014

September 18, 2014

Posted by **Bap** on Tuesday, October 9, 2012 at 2:57pm.

PROVE the difference between squared of any two terms is a multiple of 3

- Maths -
**Steve**, Tuesday, October 9, 2012 at 3:53pmsince Tn = 1+3n

(Tn)^2 = 1+6n+9n^2

(Tk)^2 = 1+6k+9k^2

(Tn)^2 - (Tk)^2 = (1+6n+9n^2) - (1+6k+9k^2)

= 6n-6k + 9n^2-9k^2

= 3(2n-2k + 3n^2-3k^2)

which is a multiple of 3 for any k,n

- Maths -
**Bap**, Tuesday, October 16, 2012 at 5:35amthanks - very much.

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