Posted by **lvf** on Tuesday, October 9, 2012 at 2:42pm.

force in the x-direction with magnitude Fx=18N-(0.530N/m)x is applied to a 5.50 box that is sitting on the horizontal, frictionless surface of a frozen lake. is the only horizontal force on the box.

what is the speed after 12m. starting from rest and x=0

- phy -
**Elena**, Wednesday, October 10, 2012 at 8:14am
F=18-0.53•x

a=F/m=(18-0.53•x)/5.5

v=sqrt(2•a•x)=sqrt[(18-0.53•x)x/5.5]=

= sqrt[(18 - 0.53•12) •12/5.5=5.04 m/s

- phy -
**n8**, Sunday, November 11, 2012 at 12:17am
the first answer is wrong

- phy -
**Alex**, Sunday, February 23, 2014 at 11:41pm
Integral of F(x) = .5mv^2

18x-.5(.53)x^2=.5mv^2

find v.

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