Posted by lvf on Tuesday, October 9, 2012 at 2:42pm.
force in the xdirection with magnitude Fx=18N(0.530N/m)x is applied to a 5.50 box that is sitting on the horizontal, frictionless surface of a frozen lake. is the only horizontal force on the box.
what is the speed after 12m. starting from rest and x=0

phy  Elena, Wednesday, October 10, 2012 at 8:14am
F=180.53•x
a=F/m=(180.53•x)/5.5
v=sqrt(2•a•x)=sqrt[(180.53•x)x/5.5]=
= sqrt[(18  0.53•12) •12/5.5=5.04 m/s

phy  n8, Sunday, November 11, 2012 at 12:17am
the first answer is wrong

phy  Alex, Sunday, February 23, 2014 at 11:41pm
Integral of F(x) = .5mv^2
18x.5(.53)x^2=.5mv^2
find v.
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