How much heat in joules is needed to raise the temperature of 5.5 L of water from 0 degrees Celsius to 78 degrees Celsius?
A block of brass is heated from 22° 30th to 78°C the mass of the block is 15 kg how much thermal energy must be added to the black of brass
To determine the amount of heat required to raise the temperature of water, we need to use the formula:
Q = mcΔT
Where:
Q = heat energy in joules
m = mass of water in kilograms
c = specific heat capacity of water (4.18 J/g·°C)
ΔT = change in temperature
First, let's convert the volume of water from liters to kilograms. We know that 1 liter of water has a mass of 1 kilogram. Therefore, 5.5 L of water has a mass of 5.5 kilograms.
Next, we calculate the change in temperature (ΔT) by subtracting the initial temperature from the final temperature:
ΔT = 78°C - 0°C = 78°C
Now we can plug the values into the formula:
Q = (5.5 kg) * (4.18 J/g·°C) * (78°C)
Let's calculate this:
Q = 5.5 kg * 4.18 J/g·°C * 78°C = 2,465.74 J
Therefore, it would take approximately 2,465.74 joules of heat to raise the temperature of 5.5 L of water from 0 degrees Celsius to 78 degrees Celsius.