Posted by Herosugar on Monday, October 8, 2012 at 10:42pm.
Okay so the acceleration g on this planet X is 15 m/s^2
I have solved for all answers but this one.
How long would it take the object to reach a height of 14.1 ? For an object thrown upward there are two times it would be at any hieght. Give the going up answer, a comma, and give the going down answer.
How do we go about this?
College Physics - Samuel, Friday, October 12, 2012 at 5:56am
Assuming that accelerations is constant,
Given: a=15 ms^-2, s=14.1 m
Applying kinematics equation,
v^2 = u^2 + 2as
Find for u since v is 0,
u= sqrt(2 x -15 x -14.1)
Solve for t,
s= ut + 0.5at^2
14.1= 20.78t + 0.5(15)t^2
//Solve quadratic eqn for t
t= 0.564(Ans), -3.33(not possible)
College Physics - Anonymous, Wednesday, December 18, 2013 at 5:41am
Solving for t,
subtract using a -15m/s^2 (downward acceleration due to gravity)
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