Posted by **Rudy** on Monday, October 8, 2012 at 9:54pm.

Write an equation of the line that passes through the point (i) parallel to the given value, and (ii) perpendicular to the given line.

Point(7,1) Line(-5x-5y=90)

- Calculus -
**Reiny**, Monday, October 8, 2012 at 10:14pm
The given line is -5x - 5y = 90

or , dividing by -5

x+y = -18

since the new line is parallel to it, its equation differs only in the costant, so let the new equation be

x+y = c , but (7,1) lies on it, so

7+1=c = 8

equation: x+y=8

If perpendicular, then the slop must be negative reciprocal : -1 ----> 1/1 = 1

new equation:

x-y = k

but (7,1) on it, so

7-1 = k = 6

x - y = 6

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