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March 25, 2017

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Write an equation of the line that passes through the point (i) parallel to the given value, and (ii) perpendicular to the given line.
Point(7,1) Line(-5x-5y=90)

  • Calculus - ,

    The given line is -5x - 5y = 90
    or , dividing by -5
    x+y = -18

    since the new line is parallel to it, its equation differs only in the costant, so let the new equation be

    x+y = c , but (7,1) lies on it, so
    7+1=c = 8

    equation: x+y=8

    If perpendicular, then the slop must be negative reciprocal : -1 ----> 1/1 = 1

    new equation:
    x-y = k
    but (7,1) on it, so
    7-1 = k = 6

    x - y = 6

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