A number has more tens than ones, but the digit in the tens place is less than 4 .the value of the ones is digit is less than 3 .what are the possible numbers?

To find the possible numbers, we need to consider the given conditions:

1. The number has more tens than ones.
2. The digit in the tens place is less than 4.
3. The value of the ones digit is less than 3.

Let's break it down step by step:

1. Since the number has more tens than ones, the tens digit can be any number from 1 to 9, excluding zero. (0 cannot be in the tens place since it would violate the condition of having more tens than ones.)

2. The tens digit is less than 4, so we can choose from the numbers 1, 2, or 3 for this position.

3. The ones digit is less than 3, meaning it can be any number from 0 to 2.

Now, let's combine the possible options for the tens and ones digits:

If the tens digit is 1, the possible ones digits are 0, 1, and 2. So, the numbers can be 10, 11, 12.

If the tens digit is 2, the possible ones digits are 0, 1, and 2. So, the numbers can be 20, 21, 22.

If the tens digit is 3, the possible ones digits are 0, 1, and 2. So, the numbers can be 30, 31, 32.

Therefore, the possible numbers that meet the given conditions are: 10, 11, 12, 20, 21, 22, 30, 31, and 32.