Posted by michelle on Monday, October 8, 2012 at 9:00pm.
first:
dy/dx = 12(1+3x)^11 (3)
= 36(1+3x)^11
when x = 0
dy/dx = 36(1)^11 = 36
and of course (0,1) is the y-intercept, so equation is
y = 36x + 1
2nd:
y = cos(x^2)
y' = 2x(-sin(x^2) = -2x sin(x^2)
use the product rule for y''
y'' = (-2x)cos(x^2) (2x) + sin(x^2) ( -2)
= -4x^2 cos(x^2) - 2sin(x^2)
I've tried entering in 36x+1 earlier and it told me it was incorrect. I thought I did it wrong. Thanks for getting back to me.
well i entered it in again and now it took that first answer. i think theres a glitch with the program but thank you for showing me how you got the answers. it helps so much!
Related Questions
calculus - Consider the curve given by the equation y^3+3x^2y+13=0 a.find dy/dx...
calculus - Find an equation of the tangent line to the curve at the given point...
Calculus - Please help this is due tomorrow and I dont know how to Ive missed a ...
Calculus - If f(x)=(3x)/(1+x^2) find f′(4). Use this to find the ...
Calculus - Damon - Find the line which passes through the point (0, 1/4) and is ...
calculus - 1. Given the curve a. Find an expression for the slope of the curve ...
calculus - Consider the curve defined by 2y^3+6X^2(y)- 12x^2 +6y=1 . a. Show ...
Calculus - Find an equation of the tangent line to the curve at the given point...
Calculus - If f(x)=(3x)/(1+x2) find f′(4)______. Use this to find the ...
calculus - Consider line segments which are tangent to a point on the right half...
For Further Reading