posted by michelle .
Find an equation of the tangent line to the curve at the given point.
y= (1+3x)^12 , (0,1)
and find y' and y"
I got y' = -2xsin(x^2)
i keep trying to get double prime but everything i try isnt working.
dy/dx = 12(1+3x)^11 (3)
when x = 0
dy/dx = 36(1)^11 = 36
and of course (0,1) is the y-intercept, so equation is
y = 36x + 1
y = cos(x^2)
y' = 2x(-sin(x^2) = -2x sin(x^2)
use the product rule for y''
y'' = (-2x)cos(x^2) (2x) + sin(x^2) ( -2)
= -4x^2 cos(x^2) - 2sin(x^2)
I've tried entering in 36x+1 earlier and it told me it was incorrect. I thought I did it wrong. Thanks for getting back to me.
well i entered it in again and now it took that first answer. i think theres a glitch with the program but thank you for showing me how you got the answers. it helps so much!