Help!

Two charges are placed on the x axis. One of the charges (q1 = +8.71C) is at x1 = +3.00 cm and the other (q2 = -28.6C) is at x2 = +9.00 cm. Find the net electric field (magnitude and direction given as a plus or minus sign) at (a) x = 0 cm and (b) x = +6.00 cm.

Why did the electric charges go on a date? They had such strong attraction! 🧲💕

Now, let's calculate the electric field at the given points. The formula for the electric field due to a point charge is:

E = k * (|q1| / r1^2) - k * (|q2| / r2^2)

Where:
E is the net electric field
k is Coulomb's constant (k = 8.99 x 10^9 Nm^2/C^2)
|q1| and |q2| are the magnitudes of the charges
r1 and r2 are the distances between the charges and the point where the electric field is being calculated.

First, let's calculate the electric field at x = 0 cm:

r1 = 3.00 cm = 0.03 m
r2 = 9.00 cm = 0.09 m

Substituting these values into the formula, we get:

E = (8.99 x 10^9 Nm^2/C^2) * (8.71C / (0.03m)^2) - (8.99 x 10^9 Nm^2/C^2) * (28.6C / (0.09m)^2)

Solving this equation will give us the magnitude and direction of the net electric field at x = 0 cm.

Now, let's move on to x = +6.00 cm or 0.06 m:

r1 = 6.00 cm = 0.06 m
r2 = 3.00 cm = 0.03 m

Using the same formula as before, we can calculate the net electric field at this point.

Remember, if you need help with the actual calculations or have any other questions, feel free to ask!

To find the net electric field at a point, you need to calculate the electric field contribution from each individual charge and then combine them algebraically.

The electric field intensity due to a point charge is given by the formula:

E = k * (q / r^2)

Where:
- E is the electric field intensity.
- k is Coulomb's constant, approximately equal to 9 x 10^9 N m^2 / C^2.
- q is the charge.
- r is the distance from the charge to the point where the electric field is being calculated.

Now let's calculate the net electric field at (a) x = 0 cm and (b) x = +6.00 cm.

(a) x = 0 cm:
To find the net electric field at x = 0 cm, you need to calculate the electric field contribution from both charges at this point and then add them.

For q1 = +8.71 C at x1 = +3.00 cm:
r1 = 3.00 cm.

E1 = k * (q1 / r1^2)

For q2 = -28.6 C at x2 = +9.00 cm:
r2 = 9.00 cm.

E2 = k * (q2 / r2^2)

The net electric field at x = 0 cm is given by:

E_net = E1 + E2

Calculate the electric field for each charge at x = 0 cm using the given values and the formula mentioned above. Then add the values together to find the net electric field (magnitude and sign).

(b) x = +6.00 cm:
Follow the same process as in part (a) to calculate the net electric field at x = +6.00 cm.

Remember to calculate the distance from each charge to the point (x = +6.00 cm) and then use the formula mentioned above to find the electric field intensity due to each charge. Finally, add the electric field contributions to find the net electric field (magnitude and sign).