Write a net ionic equation for the reaction that occurs when aqueous solutions of hydroiodic acid and barium hydroxide are combined.

H+(aq)+OH-(aq)------>H2O(l)

Okey-dokey, here's a net ionic equation for the reaction between hydroiodic acid (HI) and barium hydroxide (Ba(OH)2):

2HI(aq) + Ba(OH)2(aq) -> 2H2O(l) + BaI2(aq)

In simpler terms, it's like saying "Double HI plus Barium Hydroxide gives us double Water and Barium Iodide." Hope that clears things up!

To write the net ionic equation for the reaction between hydroiodic acid (HI) and barium hydroxide (Ba(OH)₂), we first need to write the balanced molecular equation, and then we can convert it into the net ionic equation.

The balanced molecular equation for the reaction can be written as:

2HI(aq) + Ba(OH)₂(aq) → 2H₂O(l) + BaI₂(aq)

In the balanced molecular equation, the hydroiodic acid (HI) reacts with the barium hydroxide (Ba(OH)₂) to form water (H₂O) and barium iodide (BaI₂).

Now, we can convert this balanced molecular equation into a net ionic equation by eliminating the spectator ions, which are the ions that do not take part in the actual reaction.

The complete ionic equation can be written as:

2H⁺(aq) + 2I⁻(aq) + Ba²⁺(aq) + 2OH⁻(aq) → 2H₂O(l) + Ba²⁺(aq) + 2I⁻(aq)

In the complete ionic equation, we separate the soluble compounds into their respective ions.

Now we can write the net ionic equation by removing the spectator ions, which are the ions that appear on both sides of the equation and do not participate in the reaction. In this case, the spectator ions are Ba²⁺(aq) and I⁻(aq).

The net ionic equation can be written as:

2H⁺(aq) + 2OH⁻(aq) → 2H₂O(l)

In the net ionic equation, we only include the ions that undergo a change during the reaction, which are the hydrogen ion (H⁺) and the hydroxide ion (OH⁻). These ions combine to form water (H₂O), which represents the actual reaction taking place.

Therefore, the net ionic equation for the reaction between hydroiodic acid and barium hydroxide is 2H⁺(aq) + 2OH⁻(aq) → 2H₂O(l).

2HI + Ba(OH)2 ==> BaI2 + 2H2O

net ionic:
2H^+ + 2OH^&- ==> 2H2O