You measure two different pressures of the sealed vial containing air and ethanol at two different temperatures; 89027 mmHg at 27C
and 90853 mmHg at 40C . From earlier measurements you found that the pressure of air at 27C is 76005 mmHg .
Calculate the VPethanol at both temperatures.
If the air pressure is 76005 at 27 C, then vp ethanol at 27 must be 89027-76005 = ?
For vp at 40 C I would correct air pressure at 27 to air pressure at 40 (using v1/T1 = v2/T2), then total P - air pressure at 40 C = vp ethanol at 40C.