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You measure two different pressures of the sealed vial containing air and ethanol at two different temperatures; 89027 mmHg at 27C
and 90853 mmHg at 40C . From earlier measurements you found that the pressure of air at 27C is 76005 mmHg .
Calculate the VPethanol at both temperatures.

At 27C : mmHg

At 40C : mmHg

  • Chem - ,

    If the air pressure is 76005 at 27 C, then vp ethanol at 27 must be 89027-76005 = ?
    For vp at 40 C I would correct air pressure at 27 to air pressure at 40 (using v1/T1 = v2/T2), then total P - air pressure at 40 C = vp ethanol at 40C.

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