Posted by **alth** on Monday, October 8, 2012 at 8:58am.

weather balloon is directly west of two observing stations that are 10 mi apart. The angles of elevation of the balloon from the two stations are 17.6 degrees and 78.2 degrees. How high is the balloon?

- trig -
**Reiny**, Monday, October 8, 2012 at 9:12am
Make the following diagram

Draw a base line , label the balloon as B and above the base line

Label the point directly below the balloon A on the base line

label the two stations as C and D so that

angle ACB = 78.2 and angle ADB = 17.6

Now in triangle BCD , CD = 10 ,

angle BCD = 101.8 , (exterior angle theorem)

and angle CBD = 60.6° (angle sum of triangle theorem)

Using the sine law BC/sin17.6 = 10/sin60.6

you can find BC, which is then the hypotenuse of

triangle ABC

then use

sin 78.2 = height/BC to find the height

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