Precalc/Trig 2
posted by Greg on .
The point P lies in the 4th quadrant and is located on a circle of radius 2. Find the missing coordinate for P. (___, (negative square root of 3)).

so you given y = √3
x^2 + y^2 = 2^2
x^2 + 3 = 4
x^2 = 1
x = ± 1 , but the point is in IV
so x = 1