complete and balance
Co(OH)3(aq)+Na2CO3(aq)
Is this a problem you made up yourself or one for homework? Co(OH)3 is insoluble as is Co2(CO3)3 and I'm not all that certain that a reaction will occur. It is more likely that you would get pars of both in the equilibrium mixture. Howver, this is how you balance it,
2Co(OH)3 + 3Na2CO3 ==> Co2(CO3)3 + 6NaOH
thanks DrBob222 for the answer kindly teach me what does sum coefficient mean and how to get it based from this problem
To complete and balance the chemical equation, Co(OH)3(aq) + Na2CO3(aq), we need to identify the products that are formed when these reactants combine.
The reactants are cobalt(III) hydroxide (Co(OH)3) and sodium carbonate (Na2CO3). When these two substances react, they will produce water (H2O) and cobalt(III) carbonate (Co2(CO3)3).
Now, let's balance the equation by making sure that the number of atoms for each element is the same on both sides of the equation.
Co(OH)3 + Na2CO3 → H2O + Co2(CO3)3
The number of cobalt (Co) atoms on both sides is already balanced.
The number of hydrogen (H) atoms is also balanced. There are 3 hydrogen atoms on the left side from Co(OH)3 and 3 hydrogen atoms on the right side from H2O.
Next, let's balance the oxygen (O) and carbonate (CO3) atoms:
On the left side, there are 3 oxygen atoms from Co(OH)3 and 3 oxygen atoms from Na2CO3. This gives us a total of 6 oxygen atoms on the left side.
On the right side, we have 3 oxygen atoms from H2O and 9 oxygen atoms from Co2(CO3)3, which gives us a total of 12 oxygen atoms.
To balance the oxygen atoms, we need to add a coefficient of 2 in front of the water molecule:
Co(OH)3 + Na2CO3 → 2H2O + Co2(CO3)3
Now, let's check the carbonate (CO3) atoms:
On the left side, we have 1 carbonate ion from Na2CO3.
On the right side, we have 3 carbonate ions from Co2(CO3)3.
To balance the carbonate ions, we need to add a coefficient of 3 in front of Na2CO3:
Co(OH)3 + 3Na2CO3 → 2H2O + Co2(CO3)3
Now, the equation is complete and balanced.