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CHM

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Calculate the percent ionization of hydrazoic acid (HN3) in solutions of each of the following concentrations

A) 0.377 M
B) 0.107 M
C) 4.16*10^-2 M

Ka= 1.9*10^-5

  • CHM - ,

    ..........HN3 ==> H^+ + N3^-
    I.........0.377....0.....0
    C.........-x.......x......x
    E........0.377-x....x.....x

    Ka = (H^)(N3^-)/(HN3)
    Subtitute and solve for x = (H^+). Then % ion = [(H^+)/(HN3)]*100 = ?

    Watch the lower cncns; they may require solving a qudratic.

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