Posted by **Emily ** on Sunday, October 7, 2012 at 11:29pm.

A bicycle has wheels with a diameter of 0.630 m. It accelerates uniformly and the rate of rotation of its wheels increases from 197 rpm to 300 rpm in a time of 22.5 s. Find the linear acceleration of the bicycle

- physics -
**Elena**, Monday, October 8, 2012 at 5:30pm
R=v₀•t

t=R/v₀

197 rpm = 197/60 =3.28 rev/s

300 = 5 rev/s

ω=ω₀+εt

ε= (ω-ω₀)/t =(5-3.28)/22.5=0.0076 rad/s

a = ε•R=0.0076•0.63=0.0048 m/s²

- physics -
**wally**, Monday, December 10, 2012 at 10:09pm
you forgot to convert form from frequency to angular velocity where

197rpm=3.28rev/s*2pi

apart from that the steps are accurate

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