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posted by Emily on Sunday, October 7, 2012 at 11:29pm.

A bicycle has wheels with a diameter of 0.630 m. It accelerates uniformly and the rate of rotation of its wheels increases from 197 rpm to 300 rpm in a time of 22.5 s. Find the linear acceleration of the bicycle

R=v₀•t t=R/v₀ 197 rpm = 197/60 =3.28 rev/s 300 = 5 rev/s ω=ω₀+εt ε= (ω-ω₀)/t =(5-3.28)/22.5=0.0076 rad/s a = ε•R=0.0076•0.63=0.0048 m/s²

you forgot to convert form from frequency to angular velocity where 197rpm=3.28rev/s*2pi apart from that the steps are accurate

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