Posted by Liz on .
find dy/dx of
xsinyycosx=1

Calculus...plz help!! 
Reiny,
use the product rule....
x(siny)  y(cosx) = 1
x(cosy)dy/dx + siny  y(sinx)  cosx(dy/dx) = 0
dy/dx(xcosy  cosx) = siny  ysinx
dy/dx = (siny + ysinx)/(xcosy  cosx)