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October 1, 2014

October 1, 2014

Posted by **Liz** on Sunday, October 7, 2012 at 10:26pm.

xsiny-ycosx=1

- Calculus...plz help!! -
**Reiny**, Sunday, October 7, 2012 at 10:29pmuse the product rule....

x(siny) - y(cosx) = 1

x(cosy)dy/dx + siny - y(-sinx) - cosx(dy/dx) = 0

dy/dx(xcosy - cosx) = -siny - ysinx

dy/dx = -(siny + ysinx)/(xcosy - cosx)

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