Sunday

April 20, 2014

April 20, 2014

Posted by **Liz** on Sunday, October 7, 2012 at 10:08pm.

(x^2)(y^2)-2xy+x=1 at (2, 1/2)

- calculus PLZ HELP!! -
**Reiny**, Sunday, October 7, 2012 at 10:22pm(x^2)(2y)dy/dx + 2x(y^2) - 2xdy/dx - 2y +1 = 0

dy/dx(2x^2 y - 2x) = -2x y^2 + 2y - 1

dy/dx = (-2xy^2 + 2y - 1)/(2x^2y - 2x)

at (2, 1/2)

dy/dx = (-2(2)(1/4) + 2(1/2) - 1)/(2(4)(1/2) - 4)

= (-1 + 1 -1)/0

ahh ,we are dividing by zero, so the tangent must be a vertical line

since it passes through (2, 1/2) its equation must be

x = 2

**Related Questions**

Calculus - If f(x)=(3x)/(1+x^2) find f′(4). Use this to find the equation ...

Calculus - If F(x)=x^3−7x+5, use the limit definition of the derivative to...

calculus - find the equation of a quadratic function whose graph is tangent at x...

calculus - 5. Let f be the function given by f(x) = x3- 7x + 6. a. Find the ...

Calculus - Find an equation for the tangent line of the function y=x+(4/x) at ...

Calculus - Find the equation of the tangent line to the curve y=2sinx at the ...

calculus - -find the equation of the tangent line to the curve y=5xcosx at the ...

calculus - for the function f(x)=4x^2 +7, find the equation of the tangent line ...

math calculus - Use implicit differentiation to find the equation of the tangent...

cal - find the equation of a quadratic function whose graph is tangent at x=1 to...