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December 21, 2014

December 21, 2014

Posted by **Liz** on Sunday, October 7, 2012 at 5:28pm.

- calculus =) -
**Reiny**, Sunday, October 7, 2012 at 8:00pmg ' (x) = [cos(cos(sinπx))] [-sin(cosπx) ] [cos πx] π

= -πcosπ x(-sin(cosπx)) (cos(cos(sinπx)))

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