pre calculus
posted by Natasha .
Algebraically solve the system of equations using any method you wish
3x10y+z=5
4x+9yz=6
13y+z=2

I would use substitution to start:
from the 3rd: z = 13y + 2
into the 1st:
3x  10y + 13y + 2 = 5
3x + 3y = 3
x+y=1
into the 2nd:
4x + 9y  13y  2 = 6
4x  4y = 4
x + y = 1
Ahhh,
x+y = 1 and x+y = 1 don't have a real solution.
So the system has no unique solution.
check my arithmetic