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October 1, 2014

October 1, 2014

Posted by **Natasha** on Sunday, October 7, 2012 at 5:08pm.

3x-10y+z=5

-4x+9y-z=-6

-13y+z=2

- pre calculus -
**Reiny**, Sunday, October 7, 2012 at 7:53pmI would use substitution to start:

from the 3rd: z = 13y + 2

into the 1st:

3x - 10y + 13y + 2 = 5

3x + 3y = 3

x+y=1

into the 2nd:

-4x + 9y - 13y - 2 = -6

-4x - 4y = -4

x + y = 1

Ahhh,

x+y = 1 and x+y = 1 don't have a real solution.

So the system has no unique solution.

check my arithmetic

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