Posted by Liz on Sunday, October 7, 2012 at 4:56pm.
given:
r = (1/2)h
2r = h
Let V be the volume
V = (1/3)π r^2 h
V = (1/3)π(r^2)(2r) = (2/3)π r^3
dV/dt = 2πr^2 dr/dt
when h = 10, r = 5
8 = 2π(25)dr/dt
dr/dt = 4/(25π)
Let circumference be C
C = 2πr
dC/dt = 2π dr/dt
so at that instance,
dC/dt = 2π(4/(25π) = 8/25 ft/min
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