Posted by M on Sunday, October 7, 2012 at 12:26pm.
You want to check my work very carefully. The long way of doing this is to write and balance th equation, and use stoichiometry to calculate grams CH4 need then convert that to mols. I've tried a shorter route and if you use it you may learn how to shorten some calculations also.
First I went to google and let google convert 99.3 quads BTU to megajoules. That's about 1.05E12 MJ. Then I found a page on the internet that gave the combustion of CH4 to be 38 megajoules/cubic meter. Google converts 1 cubic meter to 1000 L and 1000 L/22.4 L/mol = about 44/6 mols so 38 MJ/m^3 = 38 MJ/44.6 mol.
38 MJ/44.6 mol x # mols = 1.05E12 MJ.
And solve for # mols.
If you haven't used google for conversions yet, try it. For example covert 22.4 L to cubic meters. Type in the google window "22.4 L to cubic meters" without the quotation marks and hit the enter button. You will get the answer that 22.4L = 0.0224 cubic meters.
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