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July 24, 2014

July 24, 2014

Posted by **Travis** on Saturday, October 6, 2012 at 11:51pm.

This is a practice problem. It says the correct answer is 4e^x/(2sin(x+2y)) but I keep getting 4e^(4x)/(2cos(x+2y)).

I thought the derivative of e^(4x) would be 4e^(4x), not 4e^(x).

And I use chain rule on sin(x+2y) but I get cos(x+2y) * 2dy/dx.

Help would be appreciated, thanks!

- Calculus -
**Reiny**, Sunday, October 7, 2012 at 1:11ame^(4x) = sin(x+2y)

4e^(4x) = cos(x+2y) ***(1 + 2 dy/dx)**

4e^(4x) = cos(x+2y) + 2 dy/dx cos(x+2y) , I expanded

dy/dx = (4e^(4x) - cos(x+2y) ) / (2cos(x+2y))

looks like the supplied answer is wrong in more than one part.

I also "bolded" that part that you had wrong

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