Thursday

March 5, 2015

March 5, 2015

Posted by **Travis** on Saturday, October 6, 2012 at 11:51pm.

This is a practice problem. It says the correct answer is 4e^x/(2sin(x+2y)) but I keep getting 4e^(4x)/(2cos(x+2y)).

I thought the derivative of e^(4x) would be 4e^(4x), not 4e^(x).

And I use chain rule on sin(x+2y) but I get cos(x+2y) * 2dy/dx.

Help would be appreciated, thanks!

- Calculus -
**Reiny**, Sunday, October 7, 2012 at 1:11ame^(4x) = sin(x+2y)

4e^(4x) = cos(x+2y) ***(1 + 2 dy/dx)**

4e^(4x) = cos(x+2y) + 2 dy/dx cos(x+2y) , I expanded

dy/dx = (4e^(4x) - cos(x+2y) ) / (2cos(x+2y))

looks like the supplied answer is wrong in more than one part.

I also "bolded" that part that you had wrong

**Answer this Question**

**Related Questions**

Calculus 1 Implicit differentiation - Help please help me understand what i am ...

Calculus - Use implicit differentiation to find dy/dx if cos xy = 2x^2 - 3y. I'm...

Calculus - How do you use imlicit differentiation to differentiate e^(xy)? I ...

Calculus (repost) - Use implicit differentiation to find dy/dx if cos xy = 2x^2...

Ap Calc AB - Determine (dy/dx) using implicit differentiation. cos(X^2Y^2) = x I...

calc - If 4x2+3x+xy=2 and y(2)=–10 , find y'(2) by implicit differentiation. i ...

calc - If 4x2+3x+xy=2 and y(2)=–10 , find y'(2) by implicit differentiation. i ...

Calculus - Hi, I'm having trouble using implicit differentiation to determine dy...

Calculus: implicit differentiation - Find dy/dx by implicit differentiation 1. x...

math - the problem is 2cos^2x + sinx-1=0 the directions are to "use an identity ...