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April 24, 2014

April 24, 2014

Posted by **anonymousokm** on Saturday, October 6, 2012 at 4:58pm.

- chemistry -
**DrBob222**, Saturday, October 6, 2012 at 5:08pmI do these with two unknowns but they can be worked with just one (but it doesn't help the math).

Let x = mass CaCO3

and y = mass MgCO3

--------------------

x + y = 5.424

[x(molar mass CaO/molar mass CaCO3)] + [y(molar mass MgO/molar mass MgCO3)] = 2.791

Two equations and two unknowns. Solve for x and y (although the question doesn't want to know anything about y).

Then %CaCO3 = (mass CaCO3/mass sample)*100 = ?

Post your work if you get stuck.

- chemistry -
**anonymousokm**, Saturday, October 6, 2012 at 6:10pmthx a lot for all the help ..i got the answer 44.4 % :D

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