Tuesday

July 29, 2014

July 29, 2014

Posted by **Cole** on Saturday, October 6, 2012 at 1:31pm.

Corrals are joined together and no fencing at the back wall of the barn.

200=5d+4w

1680=4dw

What length will produce the maximum area?

d=12

The dimensions of each corral (lxw) is 12'x35'

What will be the resulting maximum combined area of 4 corrals? The combined area would also mean maximum area, correct?

A=dw

A=(4)(12)(35)=1680ft^2

- Precalculus -
**Steve**, Saturday, October 6, 2012 at 2:40pmfor maximum area, consider

a = 4dw = 4w(200-4w)/5

maximum a at w = 25 (midway between the roots of 0,50)

4dw = 75*25 = 1875 is the maximum area

**Related Questions**

Precalculus - There are 4 rectangular corrals of identical dimensions along the ...

Precalculus - I have a diagram that has 4 rectangular corrals joined together ...

Precalculus - The owner of a horse stable wishes to set up 4 rectangular corrals...

Precalculus - A barn has 150 feet of fencing and there are 3 rectangular corrals...

Precalculus - A barn has 150 feet of fencing and there are 3 rectangular corrals...

Math- Please Help Us! - Diagram has 4 rectangular corrals with a barn above it. ...

Precalculus - I usually know how to do these types of problems, but the second ...

algebra - a rancher has 310 feet of fencing with which to enclose two ...

math - A rancher has 296 feet of fencing to enclose two adjacent rectangular ...

Calculus - The owner of a farm wants to form four rectangular corrals. He has ...