Sanjeev is twice as old as his son.If after four years he will be four times as old as his son was 9 years ago ,how old is each now ??
Let's let J represent Sanjeev and x represent his son.
If J is twice as old as S then the equation is 2x=J
After four years, so J+4, he is four times as old as his son, so 4x, was 9 years ago, so x-9, if you combine all the parts of that statement you get the equation: 4(x-9)= J+4.
So now you have two different equations:
2x=J
4(x-9)=J+4
So now you just substitute. We know that J=2x from the first equation so substitute 2x in for J in the second equation and solve for x:
4(x-9)=(2x)+4
4x-36=2x+4
2x-36=4
2x=40
x=20
so now we know that the son is 20 years old. Then plug in 20 for x in the first equation to find Sanjeev's age:
2(20)=J
40=J
So Sanjeev is 40
Fabulous
Well, this seems like a tricky problem. Man, math can really age you, huh? Anyway, let's break it down.
Let's say the son's current age is X. According to the information, Sanjeev is twice as old as his son, so Sanjeev's current age is 2X.
In four years, Sanjeev's age will be 2X + 4, and the son's age will be X + 4. The problem tells us that Sanjeev's age in four years will be four times as old as his son was 9 years ago. So we can set up an equation:
2X + 4 = 4(X - 9)
Now, let's solve this equation and see what we get:
2X + 4 = 4X - 36
Subtract 2X from both sides:
4 = 2X - 36
Add 36 to both sides:
40 = 2X
Now divide both sides by 2:
X = 20
So, the son is currently 20 years old. Since Sanjeev is twice as old, he must be 2 * 20 = 40 years old.
So, Sanjeev is 40 years old and his son is 20 years old.
Phew! Math ages me faster than a rollercoaster ride.
Let's begin by assigning variables to the ages of Sanjeev and his son.
Let's say Sanjeev's current age is S, and his son's current age is Son.
According to the given information, Sanjeev is twice as old as his son, so we can write the equation:
S = 2 * Son (Equation 1)
After four years, Sanjeev will be S + 4, and his son will be Son + 4.
We are also given that after four years, Sanjeev will be four times as old as his son was 9 years ago. Mathematically, we can represent this as:
S + 4 = 4 * (Son - 9) (Equation 2)
Now we have a system of two equations (Equation 1 and Equation 2) that we can solve. First, let's substitute the value of S from Equation 1 into Equation 2:
2 * Son + 4 = 4 * (Son - 9)
Expanding the equation:
2 * Son + 4 = 4 * Son - 36
Now, simplify the equation:
4 * Son - 2 * Son = 4 + 36
2 * Son = 40
Finally, solve for Son (son's age):
Son = 40/2
Son = 20
Now that we know the son's age, we can substitute this value back into Equation 1 to find Sanjeev's age:
S = 2 * Son
S = 2 * 20
S = 40
Therefore, Sanjeev is currently 40 years old and his son is currently 20 years old.
To solve this problem, we can set up a system of equations based on the information given.
Let's say Sanjeev's current age is "S" and his son's current age is "I".
First, we know that Sanjeev is twice as old as his son, so we can write the equation:
S = 2I ...(equation 1)
Next, we're told that in four years, Sanjeev will be four times as old as his son was nine years ago. So, let's calculate their ages after four years.
Sanjeev's age after four years will be (S + 4).
His son's age nine years ago would be (I - 9).
According to the information given, we can write the equation:
S + 4 = 4(I - 9) ...(equation 2)
Now, we have a system of two equations:
S = 2I ...(equation 1)
S + 4 = 4(I - 9) ...(equation 2)
Let's solve these equations to find the values of S (Sanjeev's age) and I (son's age).
Using equation 1, we can substitute the value of S in equation 2:
2I + 4 = 4(I - 9)
Now, we can simplify the equation:
2I + 4 = 4I - 36
Subtracting 2I from both sides:
4 = 2I - 36
Adding 36 to both sides:
40 = 2I
Dividing both sides by 2:
I = 20
So, the son's current age is 20 years.
Now, we can find Sanjeev's current age using equation 1:
S = 2I
S = 2 * 20
S = 40
Therefore, Sanjeev is currently 40 years old, and his son is currently 20 years old.