Sanjeev is twice as old as his son.If after four years he will be four times as old as his son was 9 years ago ,how old is each now ??
present:
son --- x
father --- 2x
in four years:
son x+4
father 2x+4
9 years ago:
son -- x-9
father -- 2x-9
2x+4 = 4(x-9)
2x+4 = 4x-36
-2x = -40
x=20
son is now 20 , and the father is now 40
check:
in 4 years:
son is 24
father is 44
9 years ago:
son was 11
father was 30
is 44 four times 11 ? YES
To solve this problem, let's assign variables to the ages of Sanjeev and his son. Let's say the son's age is x years.
According to the problem statement, Sanjeev is twice as old as his son, so Sanjeev's age can be represented as 2x.
After four years, Sanjeev will be 2x + 4 years old, and his son will be x + 4 years old. The problem also states that in four years, Sanjeev will be four times as old as his son was 9 years ago. So we can set up the following equation:
2x + 4 = 4(x - 9)
Let's solve this equation to find the ages of Sanjeev and his son:
2x + 4 = 4x - 36
36 + 4 = 4x - 2x
40 = 2x
x = 20
So, the son's current age is 20 years. Since Sanjeev is twice as old as his son, Sanjeev's current age is 2 * 20 = 40 years.
Therefore, Sanjeev is currently 40 years old, and his son is currently 20 years old.