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November 24, 2014

November 24, 2014

Posted by **ladybug** on Saturday, October 6, 2012 at 11:29am.

f(x)=3+1n(x+2)

- pre-calculus -
**Reiny**, Saturday, October 6, 2012 at 12:51pmI think you meant to type

f(x) = 3 + ln(x+2)

we can take logs of only positive numbers, so

x+2 > 0

x > -2

ln(a number) can be any real number.

domain: x > 2

range: f(x) any real number

asymptote: none

- pre-calculus -
**Steve**, Saturday, October 6, 2012 at 2:47pmof course, there is a vertical asymptote at x = -2

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