Posted by Bru on Friday, October 5, 2012 at 10:24pm.
CH4(g) + 2O2(g) ==> CO2(g) + H2O(l)
dSo rxn = (n*dSo poducts) - (dSo reactants)
I did this and the database said the answer was wrong:
(213.8 + 70.0) - (186.2 + 2*205.0)= -312.4 j/K*mol. Am I missing something?
I'm sorry. I didn't balance the equation. I should have written (and you should have checked)
CH4 + 2O2 ==> CO2 + 2H2O(l)
Try that and see if you have better luck. Thanks for letting me know. I almost always check the equations; this time I didn't and it caught me.
Thank you!
Related Questions
chemistry - Using standard heat of formations. (Appendix II in text). Calculate ...
chemistry - for the reaction 3C2H2=> C6H6 at 25 C, the standard enthalpy ...
chemistry 2 - for the reaction 2C2H2(g)=>C6H6(l) at 25 C, the standard ...
chemistry 2 - for the reaction 2C2H2(g)=>C6H6(l) at 25 C, the standard ...
chemistry - C2H2(g) + 2 H2(g)--> C2H6(g) Substance So (J/mol∙K...
Chemistry - C2H2(g) + 2 H2(g)--> C2H6(g) Substance So (J/mol∙K...
Chemistry - C2H2(g) + 2 H2(g)--> C2H6(g) Substance So (J/mol∙K...
6 Entropy - Using the thermodynamic data provided below, calculate the standard ...
Chem - For the reaction, 3C2H2(g) ===> C6H6 at 25°C, the standard ...
Chemistry - C2H2(g) + 2 H2(g)--> C2H6(g) Information about the ...
For Further Reading