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July 28, 2014

July 28, 2014

Posted by **abhi** on Friday, October 5, 2012 at 12:30pm.

- math -
**Steve**, Friday, October 5, 2012 at 2:46pmthis one is a bit less complicated than the last one.

∫x^2/√(x-1)

Let u^2 = x-1

2u du = dx

x = 1+u^2

and we have

∫(1+u^2)^2/u 2u du

2∫(1+u^2)^2 du

2∫1 + 2u^2 + u^4 du

2(u + 2/3 u^3 + 1/5 u^5)

2/15 √(x-1)(15 + 10(x-1) + 3(x-1)^2)

2/15 √(x-1)(15 + 10x - 10 + 3x^2 - 6x + 3)

2/15 √(x-1) (3x^2 + 4x + 8)

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