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July 30, 2014

July 30, 2014

Posted by **abhi** on Friday, October 5, 2012 at 12:00pm.

- calculus -
**Steve**, Friday, October 5, 2012 at 2:37pmassuming you mean

∫(sinx + cosx)/√sin2x dx

I can think of one way: split into separate terms to get

sinx/√sin2x + cosx/√sin2x

sinx/√(2sinx cosx) + cosx/√(2sinx cosx)

1/√2 (√tanx + √cotx)

Now, I don't recall exactly the steps to integrate √tanx, but it's one of those classic problems that look simple but turn out to be quite complicated.

Visit wolframalpha.com and type in

integral √tan x

to see what I mean

Not sure what the point is to assigning such a problem. Maybe there's a typo in it here.

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