Posted by abhi on Friday, October 5, 2012 at 12:00pm.
assuming you mean
∫(sinx + cosx)/√sin2x dx
I can think of one way: split into separate terms to get
sinx/√sin2x + cosx/√sin2x
sinx/√(2sinx cosx) + cosx/√(2sinx cosx)
1/√2 (√tanx + √cotx)
Now, I don't recall exactly the steps to integrate √tanx, but it's one of those classic problems that look simple but turn out to be quite complicated.
Visit wolframalpha.com and type in
integral √tan x
to see what I mean
Not sure what the point is to assigning such a problem. Maybe there's a typo in it here.
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