Write the complete ionic equation for Cu(NO3(aq)+K2S(aq)and namd write the formula for the spectator ions in this reaction? This is what I got pls. check it:
complete ionic equation: Cu^19aq)+K^1(aq)+S^-2(aq)=K^1(aq)+NO3^-1(aq)+Cu2S(s)
net ionic equation:
Cu(aq)+s^-2(aq)=Cu2S(s)
now i can't figure out the spectator ions here pls help thanks
You have a number of what I suspect are typos but rather than take them one at a time I think it is most expedient to simply answer the questions.
I think must have meant Cu(NO3)2. The balanced molecular equation follows.
Cu(NO3)2(aq) + K2S(aq) ==> CuS(s) + 2KNO3
Then you break each of the molecules down if they are soluble and ionized. The complete ionized equation follows.
Cu^2+(aq) + 2NO3^-(aq) + 2K^+(aq) + S^2-(aq) ==> Cus(s) + 2K^+(aq) + NO3^-(aq).
Use the complete ionization equation to obtain the net ionic equation by canceling ions common to both sides.
2NO3^-(aq) occur on both sides. Cancel them. 2K^+(aq) occur on both sides. Cancel them. What's left is the net ionic equation.
Cu^2+(aq) + S^2-(aq) ==> CuS(s)
That only leaves you to name the spectator ions. Where are they? Those are the ones you canceled in the step above to obtain the net ionic equation. So K^+ and NO3^- are the spectator ions.
thanks now I understand way to go
so wrong post
Wow, it looks like you've got most of the ionic equation correct! Just a small mistake there, but no worries, I'm here to help. Let me fix that for you:
Complete ionic equation: Cu^2+(aq) + 2K^+(aq) + S^2-(aq) + 2NO3^-(aq) → 2K^+(aq) + 2NO3^-(aq) + CuS(s)
Net ionic equation: Cu^2+(aq) + S^2-(aq) → CuS(s)
Now for the spectator ions, those are the ions that appear on both sides of the equation and do not participate in the overall reaction. In this case, we have 2K^+ and 2NO3^- ions on both sides. So, the spectator ions would be K^+ and NO3^-.
To determine the spectator ions in a reaction, you need to compare the ions on both sides of the reaction and identify the ions that do not participate in the overall reaction. These ions remain the same throughout the reaction and do not contribute to the formation of any products.
Let's start by writing the balanced equation for the reaction between Cu(NO3)2 (aq) and K2S (aq):
Cu(NO3)2(aq) + K2S(aq) --> CuS(s) + 2 KNO3(aq)
Now, let's write the complete ionic equation by breaking down all the soluble compounds into their respective ions:
Cu^2+(aq) + 2 NO3^-(aq) + 2 K+(aq) + S^2-(aq) --> CuS(s) + 2 K+(aq) + 2 NO3^-(aq)
Next, let's identify the spectator ions. These are the ions that appear on both sides of the equation and do not participate in the reaction. In this case, the spectator ions are:
2 K+(aq) and 2 NO3^-(aq)
These ions do not change throughout the reaction and can be canceled from both sides of the equation. Therefore, the net ionic equation is:
Cu^2+(aq) + S^2-(aq) --> CuS(s)
In the net ionic equation, we only include the ions that are actually involved in the formation of the resulting product, CuS.
So, the formula for the spectator ions in this reaction is K+(aq) and NO3^-(aq).