Write the complete ionic equation for Cu(NO3(aq)+K2S(aq)and namd write the formula for the spectator ions in this reaction? This is what I got pls. check it:
complete ionic equation: Cu^19aq)+K^1(aq)+S^-2(aq)=K^1(aq)+NO3^-1(aq)+Cu2S(s)
net ionic equation:
now i can't figure out the spectator ions here pls help thanks
chem - DrBob222, Friday, October 5, 2012 at 3:36pm
You have a number of what I suspect are typos but rather than take them one at a time I think it is most expedient to simply answer the questions.
I think must have meant Cu(NO3)2. The balanced molecular equation follows.
Cu(NO3)2(aq) + K2S(aq) ==> CuS(s) + 2KNO3
Then you break each of the molecules down if they are soluble and ionized. The complete ionized equation follows.
Cu^2+(aq) + 2NO3^-(aq) + 2K^+(aq) + S^2-(aq) ==> Cus(s) + 2K^+(aq) + NO3^-(aq).
Use the complete ionization equation to obtain the net ionic equation by canceling ions common to both sides.
2NO3^-(aq) occur on both sides. Cancel them. 2K^+(aq) occur on both sides. Cancel them. What's left is the net ionic equation.
Cu^2+(aq) + S^2-(aq) ==> CuS(s)
That only leaves you to name the spectator ions. Where are they? Those are the ones you canceled in the step above to obtain the net ionic equation. So K^+ and NO3^- are the spectator ions.
chem - tracy, Friday, October 5, 2012 at 4:13pm
thanks now I understand way to go
chem - tracy, Friday, October 5, 2012 at 4:32pm
so wrong post