Posted by Cole on Friday, October 5, 2012 at 8:00am.
Did you make a sketch ?
Even though you didn't say, I will assume that the corrals are joined with common lengths.
let the width of the entire corral (parallel to the barn) be y ft
let each width of corrals be x ft
So we have y + 5x = 200
y = 200 - 5x
Area = xy = x(200-5x) or 200x - 5x^2
The equation will vary depending on your definition of the variables. Mine avoids unnecessary fractions .
BTW, after you maximize the area function, the dimensions of each corral will be 20 by 25, for a maximum area of 2000 for the combined area
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