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February 1, 2015

February 1, 2015

Posted by **Mike** on Thursday, October 4, 2012 at 11:33pm.

- Calculus -
**Steve**, Friday, October 5, 2012 at 5:09amarcsin(x^5y) = xy^5

1/√(1-x^10y^2) * (5x^4y + x^5 y') = y^5 + 5xy^4 y'

y' =

y^5 - 5x^4y/√(1-x^10y^2)

--------------------------

x^5/√(1-x^10y^2) - 5xy^4

you can massage that if you want to get rid of the fractions

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