Thursday

August 28, 2014

August 28, 2014

Posted by **Mike** on Thursday, October 4, 2012 at 11:33pm.

- Calculus -
**Steve**, Friday, October 5, 2012 at 5:09amarcsin(x^5y) = xy^5

1/√(1-x^10y^2) * (5x^4y + x^5 y') = y^5 + 5xy^4 y'

y' =

y^5 - 5x^4y/√(1-x^10y^2)

--------------------------

x^5/√(1-x^10y^2) - 5xy^4

you can massage that if you want to get rid of the fractions

**Related Questions**

calculus - How do you find: the Integral of arcsin(1 / (sqrt x^2 - 1) ) dx ?? (...

Calculus - Hi. In an integration solution, the integral of (1/(sqrt (8-u squared...

calculus - Please help. i am confused on how to do this one. I keep getting ...

Calculus - I'm having a little trouble with this problem...it would be great if ...

Calculus - If f(x) = 2sin(5x)arcsin(x), find f'(x).

Calculus - find the limit as x approaches 0 (arcsin x)/x

Calculus - find the derivative of g(a)=sin(arcsin(9a))

Calculus - Find the domain, range, and inverse of the function f(x)=arcsin(sqrt(...

Math (Calculus) - without any simplification, find the derivative of h(x) Arcsin...

maths - using the mean valiue thereom on f(x)=arcsin(x), show that x< arcsin(...