Posted by Bryan on Thursday, October 4, 2012 at 9:57pm.
You'll have to calculate it taking into account the different ways you could wrap the box.
If you wrap it around the perimeter perpendicular to the 7inch length, and then closing on the two 4.5x4 faces,you need wrapping paper with a length of
4.5*2+4*2 = 9+8 = 17
and width
7 + 4 = 11
or 11x17
If you wrap it around the perimeter perpendicular to the 4.5 inch side, and then closing on the two 7x4 inch sides, you need wrapping paper with a length of
7*2+4*2 = 14+8 = 22
and width of
4.5 + 4 = 9.5
or 22x9.5
If you wrap it around the perimeter perpendicular to the 4 inch side, and then closing on the two 7x4.5 inch sides, you need wrapping paper with a length of
4.5*2 + 7*2 = 14+9 = 25
and width
4+4.5 = 9.5
or 25x9.5
So you have three possibilites to wrap the gift, with sheet sizes
25x9.5
22x9.5
11x17
So 25x9.5 is out, because the other two sheets are smaller.
If you use the 22x9.5 size, you could cut three out of each 30x36 sheet of wrapping paper
If you use 11x17, you could cut out 4 out of each 30*36 sheet of wrapping paper
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