Posted by Sydney on Thursday, October 4, 2012 at 9:37pm.
There may be an easier way to do this (a graph but you didn't say you had one). You can use the Clausius-Clapeyron equation and solve for T2.
ln (p2/p1) = (dHvap/R)(1/T1 - 1/T2)
p1 = 760; T1 = 100
p2 = 520; T2 = ?
dHvap is heat vaporization in J. You'll need to look that up. T2 will be the boiling point of the water at 520 mm Hg pressure.
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