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December 18, 2014

December 18, 2014

Posted by **GS** on Thursday, October 4, 2012 at 9:13pm.

- Physics -
**Elena**, Friday, October 5, 2012 at 3:12pmAfter covering 39 m the velocity of the brick was

v=sqrt(2gH) = sqrt(2•9.8•39) =27.65 m/s.

The brick has to cover the distance 54-39 -2 =13 m.

h =vt+gt²/2

gt²+vt-2H = 0

9.8• t²+27.65•t -26 = 0

t =-27.65 ±sqrt(27.65²+4•9.8•26)/2•9.8 =

= - 27.65±42.23/19.6

t=0.74 s

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